Not sure what to do here? Plz explain. The equilibrium constant, K, of a certain

Question

Not sure what to do here? Plz explain.

The equilibrium constant, K, of a certain first order reaction was measured at two temperatures, T. The data is shown in this table. If you were going to graphically determine the enthalpy, AHC, for this reaction, what points would you plot? T (K) K 275 3.86 575 8.20 To avoid rounding errors, use three significant figures in the x values and four significant figures in the y values. Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number Number What is the standard enthalpy of this reaction? Delta A H degree = Number 7 J / mol

Explanation / Answer

point 1 = 3.64E-3 and 1.35

poit 2 = 1,74E-3 and 2.104

rise = 2.104 - 1.35 = 0.754

run = 1.74E-3 - 3.64E-3 = -3.97E2 or -396.8

slope = -396.8

delta H= (+) slope times R = 396.8 times 8.314 = 3298.9 J/mol or 3.299kj/mol

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