chem A solution of a weak acid was tested with the indicators used in this exper
ID: 710656 • Letter: C
Question
chem
Explanation / Answer
3. pH = -log[H+]
Thus, [H+] = 1.58 x 10^-5M
[OBr-] = [H+] = 1.58 x 10^-5M
[HOBr] = given = 0.10M
H+ and OBr- comes from the partial dissociation of HOBr
HOBr <=> H+ + OBr-
Ka = [H+][OBr-]/[HOBr] = 2.51 x 10^-9
pKa = -log[Ka] = 8.6
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