the active ingredient in a zinc nutrition The active ingredient in a zinc nutrit

Question

the active ingredient in a zinc nutrition The active ingredient in a zinc nutritional supplement is Znso4- 7H20 (molar mass -287.58 g/mo). Ten zinc tablets containing a mix of the active ingredient and an inactive filer were ground and m thoroughly. The total mass of these ten tablets was 10.035 g. A 1.544 g sample of the finely was dissolved in an acidic solution. The solution was ne in a water bath. Addition of (NH43PO4 to the solution resulted in the precipitation of ZnNHPO The ixed t tablets with ammonia and subsequently warmed precipitate was filtered and dried, then ignited to produce 0.158 g of ZnP:O, (molar mass - 304.76 g/mol). What is the mass percent of ZnSO4 7HzO in each tablet? Number % Znso,.7 H,0 What is the average mass of the active ingredient ZnsO4 7HO and inactive filer in each tablet? Number Number 0 g inactive filler Exit e Check AnswerNe.t Tools Give Up & View Solution O Previous Hint

Explanation / Answer

Ans. Step 1: Calculate moles of Zn in 1.544 g sample:

No matter what chemical reactions the sample is subjected to, the number of Zn-atoms must remain constant.

# Moles of Zn2P2O7 = mass / Molar mass = 0.158 g / (304.723324 g/ mol)

= 5.18503139 x 10-4 mol

# 1 mol Zn2P2O7 consists of 2 mol Zn-atom.

So, moles of Zn = 2 x Moles of Zn2P2O7 = 2 x 5.18503139 x 10-4 mol = 0.001037 mol

Therefore, total moles of Zn in 1.544 g sample = 0.001037 mol

# Step 2: Calculate mass of ZnSO4 in sample:

1 mol Zn constitutes 1 mol ZnSO4.7H2O.

So, moles of ZnSO4.7H2O in sample = 0.001037 mol

Mass of ZnSO4.7H2O in sample = Moles x Molar mass

= 0.001037 mol x (287.56056 g/ mol)

= 0.2982 g

# Step 3: Calculate % composition:

So far, we have-

                        Mass of sample = 1.544 g

                        Mass of ZnSO4.7H2O in sample = 0.2982 g

So,

            Mass of inactive filler = Mass of sample – Mass of ZnSO4.7H2O

                                                = 1.544 g – 0.2982 g           

                                                = 1.2458 g

# % ZnSO4.7H2O = (Mass of ZnSO4.7H2O / Mass of sample) x 100

                                    = (0.2982 g / 1.544 g) x 100

                                    = 19.31 %

# % Filler = (Mass of filler / Mass of sample) x 100

                                    = (1.2458 g / 1.544 g) x 100

                                    = 80.69 %

# Step 4: Calculate Average composition:

# Average mass of ZnSO4.7H2O per tablet =

(19.31 % x summed mass tabs) / no. of tabs

= (19.31 % x 10.035 g) / 10 tab

= 0.1938 g/ tab

# Average mass of Filler per tablet =

(80.61 % x summed mass tabs) / no. of tabs

= (80.61 % x 10.035 g) / 10 tab

= 0.8089 g/ tab

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