Need help with question D, please explain! thank you Constants Penodic Table Par

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Need help with question D, please explain! thank you

Constants Penodic Table Part A The semiconductor gallium arsenide, GaAs, is usad in highspeed integrated circuits, lint-emiting diodes, and solar cells. Its density is 532 e/cm It can be mada by reacting trirmathylgalliurm, Ga[CHs)s. with arsine gas, AdHs The other product of the reaction is methane, CH H you reacted 450 g af trimethylgallium with 300 g of arsine, what mass of GaAs could you maka? Express your answer to four significant figures m=5567 g Correct Significant Figures Feedback: Your answer 558 g was either rounded differendly or useda diferent number of significant igures than required for this pairt Part B Part Part D One application of GaAs uses it as a thin filim. If you take the mass of GaAs from part A and maks a 40-T.T hat 1 pm- 1x10-9 thin film from it, what area, in cm2, would it cover? Recall Express your answer to three significant figures. cm.2 Submit Request Answer

Explanation / Answer

Mass of GaAs = 556.7 g

Density of GaAs = 5.32 g/cm3

Thickness of thinfilm = 40 nm ( 1nm = 10-9 m = 10-7 cm)

Density = mass/volume =

= mass/area x thickness of thin film

=5.32 g/cm3 = 556.7 g/area x 40 x 10-7 cm

5.32 cm-2 x 4 x 10-6 x area = 556.7

Area = 556.7 x 106 / 21.28 = 26.16 x 106 cm2 = 2.62 x 107 cm2

Area = 2.62 x 107 cm2 (3 significant numbers)

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