Need assistance with Part C t Law of Definite Proportions and Atomic Theory Conr

Question

Need assistance with Part C

t Law of Definite Proportions and Atomic Theory Conrect Constarrs I Parse Tahe 2:1 berause that is the ratio wthin one single molecule. ubstans, tha mss proportons or the compoate elements wara tha sama, no mattr how muth of the substarcewasarazed. This became kmas the lew af demaite composit on ance fram constant compcsban of atoms Work ng with this concept will help You 10 beter understand the pertulale naure metter. Te answer te qesions, reier lo Ilaw mary atoms of hydrogen II arc present n 200 molcrules cf ammoria (NII? Express your answer numerically. View Available Hints) DD atoans Correct ice eachammnia mlecue cortains three hydrogen atoms, there will swasbthree times as many H atoms as there re NHs molsculc. Ernlei your anwer ummerically View Available Hint(s) Figure Habus Submit Provide Feedback Next >

Explanation / Answer

Part c

Water (H2O) molecules = 3.60*10^25

Hydrogen atoms in H2O = 2*3.60*10^25

= 7.20*10^25

Ammonia (NH3) molecules = 5.80*10^24

Hydrogen atoms in NH3 = 3*5.80*10^24

= 1.74*10^25

Total hydrogen atoms in the solution

= 7.20*10^25 + 1.74*10^25

= 8.94*10^25 atoms

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.