Problems (Usei I for all of these) 1. What volume, in L, of ethylene glycol, HOC

Question

Problems (Usei I for all of these) 1. What volume, in L, of ethylene glycol, HOCHOH, must be added to 47.73 kg of water to lower the freezing point of the water from the normal freezing point to -25.00 C? The density of ethylene glycol is 1.11 g/mL. Ethylene glycol is a non-volatile, non- ionizing solute. Ki(water) 1.86 C°/m 2. When 3950.0 mg of the compound responsible for the odor of lavender were added to 500.0 g camphor, it lowered the freezing point of camphor by 1.598 C°. What is the molecular mass of this compound? Kr for camphor is 39.7C /m. 3. The freezing point of pure camphor is 179.80°C. Kr for camphor is 39.7C°/m. How many dg of eugenol (the compound responsible for the odor of cloves) (MM eugenol 164.2 g/mol) must be added to 835.0 g camphor to reduce the freezing point to 179.65°c?

Explanation / Answer

Ans 1 :

Freezing point depression = i x kf x m

Putting all the values :

25.00 = 1 x 1.86 x m

m = 13.44 m

Molality = number of moles of solute / mass of solvent in kg

13.44 = n / 47.73

n = 641.5 mol

Mass of ethylene glycol = number of mol x molar mass

= 641.5 x 62.07

= 39819.9 g

Density = mass / volume

1.11 = 39819.9 / V

V = 35873.8 ml

or 35.9 L

So the volume of ethylene glycol that must be added will be 35.9 L

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