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EN xy-course Home secure openve se html?courseld-14901225&Open VellumHMAC-bbbb4e

ID: 716712 • Letter: E

Question

EN xy-course Home secure openve se html?courseld-14901225&Open VellumHMAC-bbbb4ee14922d0cb721961ca18e06 10001 General Biochemistry Lecture (CHEM 340)- Fall 2018 mistry Course Home CAssignment 1-Chapters 2 and 3 Problem 21 Calculate the plH values and draw the tiration curve for the Stration of 500 ml. of 0010 M aceic acld (pK, 4 76) with 0 010 MM KOH ng Part A Calculate the pH of the solution ater 0 mL of the Strant have been added Express your answer to two decimal places. pH- 339 Correct Part B Calculate the pH of the solution aher 250 mL of the ttrant have bean added Express your answer to two decimal places re to search Backs

Explanation / Answer

Total titration volume after the addition of 800 mL titrant = 500 + 800 = 1300 mL = 1.3 L

500 mL 0.010 M acetic acid will be consumed by 500 mL 0.010 M KOH.

Remaining KOH i.e. 300 mL 0.01 M will be responsible for the surplus OH- concentration.

Remaining milimoles of KOH = 300 mL x 0.01 M = 3 mmol

This mmol of KOH will be now in 1300 mL

Therefore the concentration of KOH = 3/1300 = 0.0023 M

Thus the concentration of [OH]- = 0.0023 M

Now, pOH = - log[OH-] = - log[0.0023] = - (-2.63) = 2.63

Now by definition pH + pOH = 14

                          or pH + 2.63 =14

                          or pH = 11.37