My courses/ Fall 2018 CHEM 361A-01 17273 / Lecture 5 (0913)-Adiabaic Processes a

Question

My courses/ Fall 2018 CHEM 361A-01 17273 / Lecture 5 (0913)-Adiabaic Processes and Hea tiges/Lcturs iar s 2 14 moles of a monatomic ideal gas is initally at a presure of 16.3 atm and s63 t s alowed to expandui stna pss mining 1.00 atm. Calculate the work done Iif the expansion is camied out adabatically andrevesbly, Express our answer nJoutes to te nearest whole number (xxXxx) reversibly. Express your answer in Joules to the ut of Answer: 6559 Try again abaticProcesses and Heat Engines 361A Jump to...

Explanation / Answer

Moles of gas m = 2.14 moles

Initial pressure P1 = 16.3 atm

Initial temperature T1 = 363 K

Final pressure P2 = 1 atm

Final Temperature T2 = ?

For monoatomic ideal gas

Specific heat capacity ratio n = 1.66

For adiabatic and reversible process

T2/T1 = (P2/P1)^[(n-1)/n]

T2 = 363 x (1/16.3)^[(1.66-1)/1.66]

T2 = 363 x (1/16.3)^(0.3976)

T2 = 119.66 K

Work done

W = mR(T2 - T1) / (n - 1)

= 2.14 moles x 8.314 J/mol·K x (119.66 - 363)K / (1.66 - 1)

= - 6560 J

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