The reaction NO (g) + ½ Br2 (g) NOBr (g) is second order in nitrogen oxide and f
ID: 718524 • Letter: T
Question
The reaction NO (g) + ½ Br2 (g) NOBr (g) is second order in nitrogen oxide and first order in bromine. The rate of reaction is 1.6 X 10-8 mol/L.min when the nitrogen oxide concentration is 0.020 M and the bromine concentration is 0.030 M. What is the value of K?Explanation / Answer
The reaction NO (g) + ½ Br2 (g) NOBr (g) is second order in nitrogen oxide and first order in bromine. The rate of reaction is 1.6 X 10-8 mol/L.min when the nitrogen oxide concentration is 0.020 M and the bromine concentration is 0.030 M. What is the value of K? ANSWER: NO (g) +1/2Br2 (g) -------> NOBr (g). The Rate reaction (r) = 1.6 x 10^-8 mol/L min. Formula: rate (r) = k [NO][Br2]^1/2 k = rate (r) /([NO][Br2]^1/2) k = (1.6 x 10^-8 mol/L min)/( 0.020 x( 0.030^1/2) )M^2 k = (1.6 x 10^-8 mol/L min)/( 0.020 x(0.173)M^2 k = (1.6 x 10^-8 min^-1)/(0.00346)M k = 4.62 x10^-6 M^-1min^-1
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