The reaction NO 2 ( g ) + SO 2 ( g ) ---> NO( g ) + SO 3 ( g ) seems to follow t
ID: 857969 • Letter: T
Question
The reaction NO2(g) + SO2(g) ---> NO(g) + SO3(g) seems to follow the rate law, Rate = k[NO2]2. Is the following a valid mechanism and why?
Step 1: 2 NO2(g) ---> NO3(g) + NO(g) (very fast, reversible)
Step 2: NO3(g) + SO2(g) ---> NO2(g) + SO3(g) (slow)
a
No; the overall stoichiometry of the reaction is not correct.
b
No; the derived rate law does not match the experimental law.
c
No; NO3 cannot appear in the mechanism.
d
Yes; the experimental and derived rate laws are consistent.
e
More information is needed to answer this question.
a
No; the overall stoichiometry of the reaction is not correct.
b
No; the derived rate law does not match the experimental law.
c
No; NO3 cannot appear in the mechanism.
d
Yes; the experimental and derived rate laws are consistent.
e
More information is needed to answer this question.
Explanation / Answer
b
No; the derived rate law does not match the experimental law.
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