When a piece of copper wire is placed in a colorless solution of silver nitrate,

Question

When a piece of copper wire is placed in a colorless solution of silver nitrate, the surface of the wire becomes coated with a shiny silvery material, and the copper begins to form aqueous copper(II) nitrate, which is blue. Which of the following statements regarding this reaction is correct?

Answer
The copper(II) is being oxidized.
The silver ion is being oxidized.
The nitrate ion is being reduced.
The solution will become more blue as the reaction progresses.
The reaction described is nonspontaneous.

Explanation / Answer

CU(s) + AgNO3(aq) --> Cu(NO3)2(aq) + Ag(s) As the oxidation number of both Cu and Ag ions decreases, so they are being reduced. The nitrate ion is neither being oxidised nor reduced. So the correct answer is- The solution will become more blue as the reaction progresses because the reaction will move more and more forward.

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