If in a population p = 0.9 and q = 0.1: -What genotype frequencies would indicat

Question

If in a population p = 0.9 and q = 0.1:
-What genotype frequencies would indicate that the population is in Hardy-Weinberg equilibrium?   
-What genotype frequencies would indicate that it is not in equilibrium?
-In the population that is not equilibrium, will p + q be equal to 1?
-Will p2 + 2pq + q2 be equal to 1?
-Is there any case with two alleles that p + q is not equal to 1 and p2 + 2pq + q2 is not equal to 1? If in a population p = 0.9 and q = 0.1:
-What genotype frequencies would indicate that the population is in Hardy-Weinberg equilibrium?   
-What genotype frequencies would indicate that it is not in equilibrium?
-In the population that is not equilibrium, will p + q be equal to 1?
-Will p2 + 2pq + q2 be equal to 1?
-Is there any case with two alleles that p + q is not equal to 1 and p2 + 2pq + q2 is not equal to 1? If in a population p = 0.9 and q = 0.1:
-What genotype frequencies would indicate that the population is in Hardy-Weinberg equilibrium?   
-What genotype frequencies would indicate that it is not in equilibrium?
-In the population that is not equilibrium, will p + q be equal to 1?
-Will p2 + 2pq + q2 be equal to 1?
-Is there any case with two alleles that p + q is not equal to 1 and p2 + 2pq + q2 is not equal to 1?

Explanation / Answer

Think p is dominanat and q is recessive.

p+q=1 and p=0.9 , q=0.1

so frequency of

homozygous dominanat would be 0.9x0.9= 0.81

homozygous ressesive would be 0.1x0.1=0.01

Heterozygous would be 1-0.81+0.01=0.18

If genotype frequencies differ than expected what we considered under equilibrium, we can assume that one or more of the model's assumptions are being violated, and attempt to determine which one(s). So is a population's genotype and allele frequencies will show some changs over successive generations, population is said to be in not Hardy-Weinberg equilibrium.

However even it does not follow equilibrium the p+q is to be always 1 as the sum of gene should not vary as if you see in case of ABO group where there is three gene for four phenotype the sum of A+B+I(null)=1

so p2 + 2pq + q2 would be equal to 1

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