Using average bond enthalpies (linked above), estimate the enthalpy change for t

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CO(g) + Cl2(g) ---> COCl2(g) 1. You go from a triple bond in CO to a double bond between C and O in COCl2; so you have to compute this difference of energy. 2. You loose a Cl-Cl bond and you gain 2 C-Cl bonds So, calling E1 the energy of the triple bond between C and O, E2 the energy of double bond between C and O in phosgene, E3 the bond energy Cl-Cl and E4 the bond energy C-Cl, you have, as estimated reaction energy: E2 - E1 + 2E4 - E3 ~ 128 kJ/mol with the data I've found (but remember there is quite variation on these kind of data). Edit. The reaction enthalpy is the same but with sign changed. the answer u r looking for is -100 KJ/mol.......... how i got it is by lookin at the avg bond energies for the reactants and the sum for that is 1310 and then i lloked for the the sum of the avg bond energies for the product whih is 1410..... subtract the 2 and you get -100 kj/mol

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