3. (10 points, total) Batch Reactors – First order kinetics A growth experiment

Question

3. (10 points, total) Batch Reactors – First order kinetics A growth experiment of N. oculata was carried out in a 100 L batch photobioreactor to produce a heat-stable enzyme. The doubling time of N. oculata is 4 hours. Assume dry weight of an actively growing cell of N. oculata is 2.8 x 10-12 g. Also assume first-order kinetics. (i) (5 points) Calculate the initial concentration of N. oculata cells (in # of cells/L) if the final dry weight of N. oculata after 48 hours of operation was 1.835 x 10-2 g

(ii) (5 points) A growth experiment of E. coli beginning with a single cell was carried out for 10 hours in a fermentor to produce citric acid. The doubling time of E. coli is 20 min and dry weight of an actively growing cell of E. coli is 3 x 10-13 g. Calculate the dry weight of E. coli biomass after 5 hours from the beginning of the experiment.

3. (10 points, total) Batch Reactors - First order kinetics A growth experiment of N. oculata was carried out in a 100 L batch photobioreactor to produce a heat-stable enzyme. The doubling time of N. oculata is 4 hours. Assume dry weight of an actively growing cell of N. oculata is 2.8 x 1012 g. Also assume first-order kinetics. (i) (5 points) Calculate the initial concentration of N. oculata cells (in # of cells/L) if the final dry weight of N. oculata after 48 hours of operation was 1.835 x 102g. (ii) (5 points) A growth experiment of E. coli beginning with a single cell was carried out for 10 hours in a fermentor to produce citric acid. The doubling time of E. coli is 20 min and dry weight of an actively growing cell of E. coli is 3 x 1013 g. Calculate the dry weight of E. coli biomass after 5 hours from the beginning of the experiment.

Explanation / Answer

The number of cells in the inoculum or the initial cell concentration is 1.6 × 106 cells.

3.ii

Dry weight of biomass after 5 hrs is 4.9 x 10-9 g

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