The equilibrium constant Kp for the reaction below is 0.041 at 373oC: NH4HS(s) N

Question

The equilibrium constant Kp for the reaction below is 0.041 at 373oC:

NH4HS(s) NH3(g) + H2S(g)

A sample of NH4HS(s) is placed in an evacuated container and allowed to come to equilibrium. The partial pressure of NH3(g) is then increased by the addition of 0.31 atm of NH3(g). The partial pressure of NH3(g) at equilibrium is now _________ atm.

Explanation / Answer

NH4HS(s)-----> NH3(g) + H2S(g) --------------------X;--------X Kp = 0.041 = X^2 => X = 0.2025 atm NH4HS(s)-----> NH3(g) + H2S(g) ----------0.2025+0.31-X; 0.2025-X => Kp = 0.041 = (0.51-X)(0.202-X) => X = 0.102 P(NH3) = 0.408 atm

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.