Calculate the volume of 6 M NaOH required to react completely with the amount of

Question

Calculate the volume of 6 M NaOH required to react completely with the amount of methyl salicylate you used. How much of the 6 M NaOH that you used was in excess of the theoretical amount? We started off with 2.00 mmol or 0.002 moles of methyl salicylate and we added 2.5 ml of aqueous 6 M sodium hydroxide

Here is the reaction

C8H8O3 + 2NaOH-----> disodium salicylate and water

please help

Explanation / Answer

From the balanced equation: HOC6H4COOCH3 + NaOH --> HOC6H4COO-Na+ + CH3OH One mole of NaOH is needed for every mole of methyl salcylate, therefore 10 mmole is needed. 6 M NaOH contains 6 moles/L or 6 mmole/mL, then 10 mmole / 6 mmole/mL = 1 2/3 mL

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