Research is being carried out on cellulose as a source of chemicals for the prod

Question

Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings, and plastics. Cellulose consists of long chains of glucose molecules (C6H12O6), so for the purposes of modeling the reaction we can consider the conversion of glucose to formaldehyde (H2CO). Calculate the heat of reaction for the conversion of 1 mole of glucose into formaldehyde, given the following thermochemical data: H2CO(g) + O2(g) rightarrow CO2(g) + H2O(g) Delta H degree comb = - 572.9 KJ/mol 6 C(s) + 6 H2(g) + 3 O2(g) rightarrow C6H12O6(s) DeltaHdegree f = - 1274.4 KJ/mol C(s) + O2(g) rightarrow CO2(g) DeltaHdegree f = - 393.5 KJ/mol H2(g) + 1 / 2 O2(g) rightarrow H2O(g) DeltaHdegree f = - 285.8 KJ/mol C6H12O6(s) rightarrow 6 H2CO(g) DeltaHdegree rxn = ?

Explanation / Answer

heat of reaction is the difference in the heats of products and reactants
Heat of formation of H2CO is
-572.9=H(CO2)+H(H2O)-H(H2CO)

-572.9=-393.5-285.5-H(H2CO)

H(H2CO)=-106.1

hence the heat of conversion is -106.1*6-(-1274.4)=637.6

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.