you have a valid solution. But if the answer is no, you need to go back and chan
ID: 74946 • Letter: Y
Question
you have a valid solution. But if the answer is no, you need to go back and change one of your hypotheses, redo the Punnett square, and check to see if the predictions and observations match. Keep redoing yes, these steps until you have a model that fits the data. 11. In the plant species Plectritis congesta, known as rosy plectritis, in- dividuals produce fruits that either have or do not have prominent structures called wings. The alleles involved are wr-winged fruit; W" = wingless fruit. Researchers collected an array of individuals from the field and performed a series of crosses. The results are given in the table below. Complete the table by writing down the genotype of the parent or parents involved in each cross. (Write down one genotype if selfing occurs and two genotypes if two differ- ent individuals were involved.) Number of Number of Offspring Offspring with Winged Fruits with Fruits 80 Parental Phenotype(s) Wingless Parental Genotype(s) Wingless (self-fertilized) Winged 90 30 (self-fertilized) Winged × wingless 0 Winged × winged 44 0 12. Tay-Sachs disease causes nerve cells to malfunction and results in death by age 4. Two healthy parents know from blood tests that each parent carries a recessive allele responsible for Tay-Sachs. If their first three children have the disease, what is the probability that their fourth child will not? Assuming that they have not yet had a child, what is the probability that, if they have four children, all four will have the disease? If their firer
Explanation / Answer
alleles and genotypes in ABO blood group:
Offspring genotypes-without bracket
Phenotypes-within the bracket
Both A and B alleles are dominant over O. As a result, individuals who have an AO genotype will have an A phenotype. People who are type O have OO genotypes. In other words, they inherited a recessive O allele from both parents. The A and B alleles are codominant. Therefore, if an A is inherited from one parent and a B from the other, the phenotype will be AB. Agglutination tests will show that these individuals have the characteristics of both type A and type B blood.
O type woman married with AB type man:
1/2 A type and 1/2 B type blood group children observed.
11 Ans:
parent alleles A B O A AA(A) AB(AB) AO(A) B AB(AB) BB(B) BO(B) O AO(A) BO(B) OO(O)Related Questions
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