The reaction of combustion of ethanol is this: C2H5OH(g) +3O2(g) ---> 2CO2(g) +

Question

The reaction of combustion of ethanol is this: C2H5OH(g) +3O2(g) ---> 2CO2(g) + 3H2O (g) Los regalitos son ( g ) Lis 4 tienen(g ) A) calculate delta H of the reaction in kj/mol B) how many heat,in kj, the combustion liberates of 200 g of ethanol C)if i want to heat 500 g of liquid water since 17C to 85 C. How many grams of ethanol should be burn to get the required heat? The specific heat of water is 4.184 J/gC Additional data: C2H5OH (G) --- -235.31 O2 (G) ----- 0 CO2 (G) ------- -393.5 H2O (G) ---- -241.83

Explanation / Answer

The reaction of combustion of ethanol is this: C2H5OH(g) +3O2(g) ---> 2CO2(g) + 3H2O (g) Los regalitos son ( g ) Lis 4 tienen(g ) A) calculate delta H of the reaction in kj/mol B) how many heat,in kj, the combustion liberates of 200 g of ethanol C)if i want to heat 500 g of liquid water since 17C to 85 C. How many grams of ethanol should be burn to get the required heat? The specific heat of water is 4.184 J/gC Additional data: C2H5OH (G) --- -235.31 O2 (G) ----- 0 CO2 (G) ------- -393.5 H2O (G) ---- -241.83 solution: delta H = -1.37 x 10^3 KJ 1 mol ethanol will release 1.37*10^3kJ 46.1g ethanol will release 1.37*10^3kJ 15.1g ethanol will release 15.1/46.1*(1.37*10^3)kJ 448.7kJ..............................................................Ans

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