Technetium is not found naturally on earth; it must be synthesized in the labora

Question

Technetium is not found naturally on earth; it must be synthesized in the laboratory. Nonetheless, because it is radioactive, it has valuable medical uses. For example, the element in the form of sodium pertechnetate (NaTcO4) is used in imaging studies of the brain, thyroid, and salivary glands and in renal blood flow studies, among other things. a) In what group and period of periodic table is the element found? b) List the set of quantum numbers for each of Technetium

Explanation / Answer

itanium(IV) oxide, TiO2, is heated in hydrogen gas to give water and a new titanium oxide, TixOy. If 1.598 grams of TiO2 produces 1.428 grams of TixOy, what is the formula of the new oxide ? TiO2 + H2 --> TixOy+ H2O my guess is that the product is Ti2O3 1.428gTixOy produced 1.598g TiO2 / 79.9g/mole = 0.02moles TiO2 1.428g TixOy / 0.02moles = 71.4g/mole TixOy 71.4g - 48g = 23.4g O....23.4g O / 16g/mole = 1.46moles O therefore, Ti = 1 and O = 1.5 for the molecular formula, Ti2O3 4. (i) energy, shape (ii) 0, 1, 2 (iii) d (iv) 4, 2, (-2, -1, 0, 1, 2) (v)? (vi) ? 5. (20 pts - [S11.A.3.3.1, S11.A.3.3.2, S11.C.1.1.2, S11.C.1.1.3]) Technetium is not found naturally on earth; it must be synthesized in the laboratory. Nonetheless, because it is radioactive it has valuable medical uses. For example, the element in the form of sodium pertechnetate (NaTcO4) is used in imaging studies of the brain, thyroid, salivary glands and in renal blood flow studies, among other applications. (a) group 7b, period 5: look at the periodic table (b) 5, 0, 0, +/-1 (c) C = wavelength x frequency E = planck's constant x frequency 9.6485x10^4J/mole x 141eV = 13604385J or 1.36x10^7J 1.36x10^7J / 6.626x10^-34J-sec = 2.05x10^40/sec = frequency 3x10^8m/sec / 2.0510^40/sec = 1.46x10^-32m = wavelength (d) To make NaTcO4, the metal is dissolved in nitric acid 7 HNO3(aq) + Tc(s) ---> HTcO4(aq) + 7 NO2(g) + 3 H2O(l) and this product, HTcO4, is treated with NaOH to make NaTcO4. (i) HTcO4 + NaOH --> NaTcO4 + H2O (ii) 7 HNO3(aq) + Tc(s) ---> HTcO4(aq) + 7 NO2(g) + 3 H2O(l) HTcO4 + NaOH --> NaTcO4 + H2O 0.0045g / 98g/mole = 4.6x10^-5moles Tc this yields 4.6x10^-5moles HTcO4 this yields 4.6x10^-5moles NaTcO4 = 0.00851g or 8.51mg 4.6x10^-5moles HTcO4 requires 4.6x10^-5moles NaOH 4.6x10^-5moles x 40g/mole = 0.00184g or 1.84mg

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