Consider the following formation reaction: Mg(s) + 1/2O2(g) -------- MgO(s) ----

Question

Consider the following formation reaction: Mg(s) + 1/2O2(g) -------- MgO(s) -------- ?H = -601.8 kJ a) Is the reaction exothermic or endothermic? b) What is the enthalpy of the opposite reaction? Please explain this question in detail to me because i am really lost Please do not answer if you are just going to answer the question if you are going to post a retarded answer on how i should learn thing ...because i am trying to learn how to do this and i have been trying to work it out all night. And my teacher made this an open class question not a homework question but i need to learn this for a test.

Explanation / Answer

When enthalpy value is negative, it is exothermic reaction.

When enthalpy value is positive, it is endothermic reaction.

Here, the enthalpy value is -ve, so it is exothermic reaction.

For the opposite reaction, the enthalpy would remain same with the sign reversed.. which means the enthalpy of opposite reaction would be +601.8 kJ

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