What is the orbital angular momentum of an electron in the orbitals a) 1s b) 2p

Question

What is the orbital angular momentum of an electron in the orbitals a) 1s b) 2p c) 3s d) 3p e) 3d? In each case, give the number of angular and radial nodes.

Explanation / Answer

To find the orbital angular momentum use the equation: w = ([l(l+1)]^1/2)h --> the number of angular nodes = l --> the number of radial nodes = n - l - 1 a) n = 1, l = 0 therefore w = 0 there are 0 angular nodes and 0 radial nodes b)n = 2, l = 1 w= [1(1+1)]^1/2(6.626e-34 J s) = .935x10^-33 J s there are 2 angular nodes and 0 radial nodes c) n = 3, l = 0 therefore w = 0 there are 0 angular nodes and 2 radial nodes d)n = 3, l = 1 w = [2(2+1)]^1/2(6.626e-34 J s) = 1.62x10^-33 J s e) n = 3, l = 2 w = [2(2+1)]^1/2(6.626e-34 J s) = 1.62x10^-33 J s there are 2 angular nodes and 0 radial nodes

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