Complex Ion Formation: Cu(NH3) 4 2+ E cell, after adding 6 M NH3 to the copper c
ID: 76218 • Letter: C
Question
Complex Ion Formation:Cu(NH3)42+ Ecell, after adding 6 M NH3 to the copper cell_________ V. Calculate the concentration of that free copper (II) ionthat is in equilibrium with the complexed copper (II) ion,Cu(NH3)42+ in the solution. Does the calculated value make sense and what does it imply? Complex Ion Formation:Cu(NH3)42+ Ecell, after adding 6 M NH3 to the copper cell_________ V. Calculate the concentration of that free copper (II) ionthat is in equilibrium with the complexed copper (II) ion,Cu(NH3)42+ in the solution. Does the calculated value make sense and what does it imply?Explanation / Answer
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