Completed in 2003, the sequence of the human species genome describes the 99.9%
ID: 141681 • Letter: C
Question
Completed in 2003, the sequence of the human species genome describes the 99.9% of DNA that all humans have in Since 2003, a research team called the International HapMap Consortium has been characterizing the remaining 0.1% of the human genome that varies in sequence among individuals. So far, they have identified millions of these sites, the variations at each site, and the relative frequency of each variation among four selected populations, as listed in the adjacent table. Verified Ancestry Location Utah, United States Beijing, China Tokyo, Japan Ibadan, Nigeria Abbreviation CEU CHB PT YRI | Western European Han Chinese Ja panese Yoruba One site of particular interest is called rs 12913832 and is found in the HERC2 gene of chromosome 15. One of two possible base pairs is found at this site: A or G. Examine the following genotype data obtained by sequencing individuals chosen at random from each of the four populations. You can use these data to determine the allele frequency of the two alleles in each population. Complete the table by entering the allele frequencies of the CEU population. Round your answers to the nearest hundredth. Number of Individuals Sequenced Frequency Population Total Genotype AA Genotype AG Genotype GG Allele A Allele G CEU CHB PT 113 45 45 63 39 70 1.00 1.00 1.00 0.00 0.00 0.00 45 63 O Type here to search 8 2Explanation / Answer
1) The frequency of allele A in CEU population is,
= (4 + (39/2))/113
= (4 + 19.5)/ 113
= 23.5/113
= 0.208
The frequency of allele G in CEU population is,
= (70 + (39/2)) / 113
= (70 + 19.5)/113
= 89.5/113
= 0.792
2) Genetic drift acting in past generations produce the observed differences in allele frequencies between the populations.
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