The following reaction takes place at high temperature. (Equation not balanced.)

Question

The following reaction takes place at high temperature. (Equation not balanced.) Fe3O4 + C ? Fe + CO2 How many grams of Fe can be made from the reaction of 21.2 grams of C with excess Fe3O4?

Explanation / Answer

Balanced Chemical Equation: Fe3O4 + 2C --> 3Fe + 2CO2 Since the question states there is excess Fe3O4, C must be the limiting reagent. First, we solve for the moles of C: 21.2 g x 1 mol/12.01 g = 1.77 moles Now, from the balanced chemical equation, we can solve for the moles of Fe: 1.77 moles of C x 3 moles of Fe/2 moles of C = 2.66 moles Now, from the moles of Fe, we can solve for the grams of Fe from its mass: 2.66 moles x 55.85 g/mol = 148.56 g Hope this helps! :)

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