2HI(g) + Cl2(g) <==> 2HCl(g) + I2(s) This is all the information presented to so

Question

2HI(g) + Cl2(g) <==> 2HCl(g) + I2(s) This is all the information presented to solve the equation. The steps i've taken are as follows: 2mol HI, 1mol Cl2 <==> 2mol HCl, 1mol I2(s) Kc= [ (HCl)^2 x (I2) ] / [ (HI)^2 x (Cl2) ] My question at hand comes from how to figure out the concentrations of each; considering the values of these reactants, and products are supposed to be expressed in molarity (if i am not mistaken). Am i supposed to use a standard liter amount to convert the moles of each product and reactant into molarity?

Explanation / Answer

if values of volumes of container is given we have to use it for calculating concentrations M= no of moles/(vol of container in liters) if vol not given we assume vol of container = 1liter hence no of moles = M

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