a). a solution is prepared by mixing 1.000 mole of methanol(CH3OH) and 2.38 mole

Question

a). a solution is prepared by mixing 1.000 mole of methanol(CH3OH) and 2.38 mole of propanol (CH3CH2CH2OH). what is the composition of the vapor (in mole fractions) at 40 degrees Celsius? vapor pressures at 40 degrees celsius: -pure methanol: 303 torr -pure propanol: 44.6 torr CH3OH mole fraction in the vapor=?? propanol mole fraction in the vapor=?? b). what is the composition of the vapor of a pentane/hexane solution that has a vapor pressure of 385 torr at 25 degrees celsius? vapor pressures at 25 degrees celsius: pentane mole fraction in the vapor?? hexane mole fraction in the vapor??

Explanation / Answer

Xm = Pm * Nm /(Pm * Nm + Pp * Np)

= 303/303+44.6*2.83

= 0.7059

Xp = 1-Xm

=0.2940

b)

vaour pressure = Ppen * Xpen + Phex * Xhex

385 = Ppen * Xpen + Phex * (1- Xpen)

385 = 511 * Xpen + 150 - 150*Xpen

Xpen = 0.650

Xhex = 1- Xpen = 0.349

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