A 1.606 sample of a component of the light petroleum distillate called naphtha i

Question

A 1.606 sample of a component of the light petroleum distillate called naphtha is found to yield 4.923 and 2.351 on complete combustion. This particular compound is also found to be an alkane with one methyl group attached to a longer carbon chain and to have a molecular formula twice its empirical formula. The compound also has the following properties: melting point of 154 , boiling point of 60.3 , density of 0.6532 at 20 , specific heat of 2.25 , and ^h =-204.6 . Enthalpies of formation Here are enthalpy of formation values, , for selected substances: Substance 204.6 0 393.5 285.8 Calculate the enthalpy of combustion, , for . You'll first need to determine the balanced chemical equation for the combustion of . Express your answer to four significant figures and include the appropriate units.

Explanation / Answer

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