A 1.500 g of sample of BaCl2 x H2O was heated until all of the water was removed

Question

A 1.500 g of sample of BaCl2 x H2O was heated until all of the water was removed. The residue after heating weighed 1.268 g. Below is the partial data sheet that ate required to fill out in the lab. Complete the following data sheet and show all the calculations on the separate calculations page. Mass of water in the hydrate grams % water of hydration Molecular weight of anhydrate g/mol Moles of anhydrous compound remaining Moles of water removed Mole ratio of water to anhydrate = 1 (H2O:Anhydrate) Chemical Formula of the hydrate Chemical name of the hydrate

Explanation / Answer

a)   0.232 g H2O                                        1.500 - 1.268 = 0.232 g H2O

b) 15.47 % water of hydration                    (0.232 / 1.5) x 100

c)   208.23 g/ mol   (standard)

d) 0.0061 moles                                            208.23 /1.268 = 0.0061

e) 0.013 moles of water                             0.232 / 18 =    0.013

f)   0.013 : 0.0016                                      

g) BaCl2.2H2O

h) hydrated barium chloride (octa hydrate)

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