1-Propanol, C3H8O can be oxidized by NaOCl, to propionic acid C3H6O2 and NaCl. B

Question

1-Propanol, C3H8O can be oxidized by NaOCl, to propionic acid C3H6O2 and NaCl. Balance these half cells using the half cell method. You do NOT need to balance the entire redox reaction. C3H8O --> C3H6O2 OCl-(aq) --> Cl- (aq) Can anyone answer and explain how to do this?

Explanation / Answer

C3H8O + 4OH- --> C3H6O2 + 3H2O + 4e- ........................OCl- + H2O + 2e------> Cl- + 2OH- ......................Explanation....C3H8O --> C3H6O2 ,.....Balance O in each side by addition of H2O ....=> C3H8O + H2O -----> C3H6O2 ..............Now balance H by adding H+ ......=> C3H8O + H2O ------> C3H6O2 + 4H+ ........Since the medium is basic H+ will not remain. Hence add 4OH- on both sides ......=> C3H8O + H2O + 4OH- ------> C3H6O2 + 4H+ + 4OH- .......(H + +OH- ---> H2O) ......=> C3H8O + H2O + 4OH-------> C3H6O2 + 4H2O ........=> C3H8O + 4OH- --> C3H6O2 + 3H2O + 4e- (Add 4 e- for charge balance) ........For OCl-(aq) --> Cl- ...........OCl- ----> Cl- + H2O .............OCl- + 2H+ ------> Cl- + H2O ...........OCl- + 2H+ + 2OH- -------> Cl- + H2O + 2OH- ...........=> OCl- + H2O + 2e------> Cl- + 2OH-

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