015 (part 1 of 2) 10.0 point:s Consider a variation of Bohr\'s 1913 model of the
ID: 777047 • Letter: 0
Question
015 (part 1 of 2) 10.0 point:s Consider a variation of Bohr's 1913 model of the hydrogen atom, where the electron is in a circular orbit of radius 4 x 10-11 m speed is 2.51625 x 106 m/s , and its What is the magnitude of the magnetic moment due to the electron's motion? Answer in units of A m 016 (part 2 of 2) 10.0 points If the electron orbits counterclockwise in a horizontal circle as viewed from above up- ward, what is the direction of this magnetic moment vector? 1. radially inward 2. radially outward 3. upward 4. radially directed; sometimes inward and sometimes outward 5. downward 017 (part 1 of 2) 10.0 points and area 0.11 m A circular coil of 255 turns is in a uniform magnetic field of 0.58 T. The maximum torque exerted on the coil by the field is 0.0012 N m. Calculate the current in the coil. Answer in units of A 018 (part 2 of 2) 10.0 points Assume the 255 turns of wire are used to form a single-turn coil with the same shape but much larger area. What is the current if the maximum torque exerted on the coil by the field is 0.0012 N·m? Answer in units of A,Explanation / Answer
Solution:
16.1) Magnitude of magnetic moment is given by M = e * v * r / 2
=> M = 1.6 x 10^-19 * 2.51625 * 10^6 * 4 * 10^-11 / 2
=> M = 8.052 * 10 ^-26 Am^2
16.2) Magnetic Moment vector will be radially inward. Using Right hand rule.
17) Maximum torque is given by,
=> Torque = I * B* A * N
=> 0.0012 = 255 * 0.11 * 0.58 * I
=> I = 7.37 * 10^(-5) A
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