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part A and B a.com/Common/TakeTutorialAssignment.aspx Student: jorge.sosa@mavs.u

ID: 777906 • Letter: P

Question

part A and B

a.com/Common/TakeTutorialAssignment.aspx Student: jorge.sosa@mavs.utaedu My Account Log Out HW 5: Circular motion Begin Date: 3/4/20181 0 PM End Date: 3/24/2018 11:59:00 PM (9%) Problemi 7: A nail is stuck in the 0.6I N. The nail has a mass of m-11g. tread of a tire with radius r-0.16 m. It is held an with amain um frictional force ofF & 50% Part (a) what is the tire tread's lowest tangential speed in meters per second, at which the nail will pull free from the tire? Assume the tire is spinning vertically but not in coatact with the road. Grade Summary potential 100% eted eted eted bnissio cos) asin atan) acotan)sinh) cosh() | tanh()-cotan1s( ) Attempts remaining: (5% per attempt) detailed view cotan) acosl) eted eted DegreesRadians llmt leted leted leted leted Hints: 0t% deduction per hunt Hinds remaining Feedback:2% deduction per feedback Part (b) At what tangential speed. in meters per second, will the nail pull free when it is at the top of the tire? 202 PM

Explanation / Answer

here,

mass of nail , m1 = 11 g = 0.011 kg

r = 0.16 m

ff = 0.61 N

a)

let the tangential speed be v

for the lowest tangential speed,

at the bottom

ff = m * ( g + v^2 /r)

0.61 = 0.011 * ( 9.81 + v^2 /0.16)

solving for v

v = 2.7 m/s

b)

for the nail pull free at the top of tire

let the tangential speed be v

at the top

ff = m * ( v^2 /r - g)

0.61 = 0.011 * ( v^2 /0.16 - 9.81)

solving for v

v = 3.23 m/s