When solving, can you please explain part b in more detail. Like what is the gen

Question

When solving, can you please explain part b in more detail. Like what is the general formula that is used. Thanks!

Problem #3 A 5.0 kg mass hanging from a spring scale is slowly lowered on to a vertical spring, as shown in this figure. The scale reads in newtons. a. What does the spring scale read just before the mass touches the lower spring? b. The scale reads 20 N when the lower spring has been compressed by 2.0 cm. What is the value of the spring constant for the lower spring? At what compression will the scale read zero? c. Scale -

Explanation / Answer

Given that,

m = 5.00 kg

spring sclae reads just before touches the lower spring is

W = m*g

= 5.00 * 9.8

= 49.0 N

b) Given that

W1 = 20 N

W = 49 N

x = 0.02 m

Force of lower spring that pushes upward is

W1 = F + W

F = -kx

W1 = (-kx) + W

-kx = W1 - W

k = -((W1 - W)/x)

k = -((20 - 49) / 0.02)

k = 1450 N/m

c) The Equation for compression length at which the scale read zero is,

W + F = 0

W - kx = 0  

kx = W

x = W / k

= 49 N / 1450 N/m

= 0.03379 m or 3.379 cm

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.