Part E Now assume that the pitcher in Part D throws a o 165 kg baseball parallel
ID: 778807 • Letter: P
Question
Part E Now assume that the pitcher in Part D throws a o 165 kg baseball parallel to the ground with a speed of 19.0 m/s in the -x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line What is the ball's x-component of velocity just after leaving the bat if the bat applies an impulse of +6.9 N-s to the baseball? Enter your answer numerically in meters per second using two significant figures. 60.8182 Submit X Incorrect; Try Again; 5 attempts remaining m/s V. = Previous Answers Request AnswerExplanation / Answer
Impulse = change in momentum
dp = m(v2 - v1)
6.9 = 0.165*(v2 - 19)
v2 = 60.81 m/s
so please try with value 61 m/s as the answer
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