IS exactly the Same as the Tree-body dlagram We would draw Tor a bOx belng pulle
ID: 779314 • Letter: I
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IS exactly the Same as the Tree-body dlagram We would draw Tor a bOx belng pulled to the right across a rough horizontal table by a rope. If we employ the same thinking we used to determine the sign of the work done by each of the forces acting on the box, we can check whether the signs of our calculations for the work done by each force on the sled make sense. WT should be positive (which it is) Now let's consider the total work done on an object that has several forces acting on it. A tractor is hitched to a sled loaded with firewood and pulls the sled a distance of 20.0 m along level frozen ground (Figure 1). The total weight of the sled and load is 14,700 N. The tractor exerts a constant force FT with magnitude 5000 N at an angle of 36.9° above the horizontal, as shown. A constant 3500 N friction force opposes the motion. Find the work done on the sled by each foce individually and the total work done on the sled by all the forces W should be negative (which it is), and W, and Wn should be zero. A natural question to ask is: Where did the energy associated with Wtotal go? We will return to this question later in this chapter Part A - Practice Problem Suppose the tractor pulls horizontally on the sled instead of at an angle of 36.9 As a result, the magnitude of the friction force increases to 3700 N. What is the total work done on the sled? Figure Express the work in joules to three significant figures 3700 Submit Previous Answers Request Answer (a) A tractor pulls a sled. X Incorrect, Try Again: 5 attempts remaining K Return to Assignment Provide FeedbackExplanation / Answer
work done by tractor force WT = FT*s*cos0
work done by tractor force WT = 5000*20*cos0 = 100000 J
work done by friction force Wf = f*s*cos180
work done by tractor force Wf = 3700*20*cos180 = -74000 J
perpendicular to surface
Fn - Fg = 0
normal force Fn = Fg = m*g
work done by normal force Wn = Fn*s*cos90 = 0
work done by gravitational force Wg = Fg*s*cos90 = 0
total work done = WT + Wf + Wn + Wg = 100000 - 74000 = 26000 J <<<----ANSWER
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