The following questions all refer to an aqueous 8.57 M potassium acetate stock s
ID: 779368 • Letter: T
Question
The following questions all refer to an aqueous 8.57 M potassium acetate stock solution.
1. If 17.6 mL of the stock solution are diluted to 952 mL, what is the molarity (in mol/L) of the new solution?
2. If 25.4 mL of the stock solution are diluted to obtain a 0.525 M potassium acetate solution, what is the volume (in mL) of the new solution?
3. Determine the volume (in mL) of the original stock solution that must be used to prepare 413 mL of a 0.483 M potassium acetate solution.
4. Determine the volume of water (in mL) that was added to 12.8 mL of the stock solution to prepare a 0.183 M potassium acetate solution.
Explanation / Answer
M1*V1=M2*V2
1)
8.57*17.6 = 952*M2
M2 = 0.158M
2)
8.57*25.4=0.525*V2
V2=414.625ml
3)
V1*8.57=413*0.483
V1 = 23.276ml
4)
8.57*12.8 = 0.183(12.8+V)
V = 586.63 ml
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