VI In the titration of a .987 g sample of vinegar with 1.00 M NaOH, 0.85 ml of s
ID: 784119 • Letter: V
Question
VI
In the titration of a .987 g sample of vinegar with 1.00 M NaOH, 0.85 ml of sodium hydroxide was used.
(5)
________
Calculate the moles of acetic acid in the vinegar sample
(5)
________
Calculate the grams of acetic acid in the sample (MW of acetic acid = 60 g/mole)
(5)
________
Calculate the mass percent of acetic acid in the sample of vinegar.
VI
In the titration of a .987 g sample of vinegar with 1.00 M NaOH, 0.85 ml of sodium hydroxide was used.
(5)
________
Calculate the moles of acetic acid in the vinegar sample
(5)
________
Calculate the grams of acetic acid in the sample (MW of acetic acid = 60 g/mole)
(5)
________
Calculate the mass percent of acetic acid in the sample of vinegar.
Explanation / Answer
5) moles of acetic acid in the vinegar sample = moles of NaOH consumed = 0.85*10^-3*1 = 0.85*10^-3 moles of acetic acid
6)Mass of acetic acid = no.of moles*molecular weight = 0.85*10^-3*60 = 0.051 gm = 51 mg
7)weight % of acetic acid = wt of acetic acid/weight of sample)*100 = 0.051/0.987)*100 = 5.167%
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