The specific heat of aluminum is 0.902 J/g .degrees C. How much heat is absorbed
ID: 784623 • Letter: T
Question
The specific heat of aluminum is 0.902 J/g .degrees C. How much heat is absorbed by an aluminum pie tin with a mass of 473g to raise its temperature from room temperature (23.00 degrees C)to overn temperature (375 degrees Farenheit)? Please explain your answer. Thank you!! The specific heat of aluminum is 0.902 J/g .degrees C. How much heat is absorbed by an aluminum pie tin with a mass of 473g to raise its temperature from room temperature (23.00 degrees C)to overn temperature (375 degrees Farenheit)? Please explain your answer. Thank you!!Explanation / Answer
Heat=mass*Specific heat *temperature difference
= 473*0.902*(190-23)
=71486J
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