Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A sample of an unknown peptide undergoes a single round of Edman degradation, wh

ID: 786077 • Letter: A

Question

A sample of an unknown peptide undergoes a single round of Edman degradation, which liberates ATZ-Gly. Another sample of the peptide is treated with trypsin, and a third sample is treated with chymotrypsin. The table below shows the fragments.


Tryptic fragments:

Phe-Ser

Gly-Val-Tyr-Arg

Asn-Tyr-Ala-Pro-Thr-Cys-Val-Gln-Lys


Chymotryptic fragments:

Arg-Asn-Tyr

Ala-Pro-Thr-Cys-Val-Gln-Lys-Phe

Ser

Gly-Val-Tyr


A) line up the fragments so that the fragments with the same sequences overlap.


B) Write the sequence of the peptide

Explanation / Answer

Edman degradation removes amino acid fron N-terminal,

so, as Gly is liberated during Edman degradation, it means Gly is at the N- terminal

A)


Tryptic fragments: will be lines up as

Gly-Val-Tyr-Arg ---Asn-Tyr-Ala-Pro-Thr-Cys-Val-Gln-Lys ---- Phe-Ser


Chymotryptic fragments: will be lined up as

Gly-Val-Tyr --- Arg-Asn-Tyr ---- Ala-Pro-Thr-Cys-Val-Gln-Lys-Phe --- Ser


B)

sequence of the peptide is

Gly-Val-Tyr-Arg -Asn-Tyr-Ala-Pro-Thr-Cys-Val-Gln-Lys- Phe-Ser

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote