A sample of an unknown peptide undergoes a single round of Edman degradation, wh

Question

A sample of an unknown peptide undergoes a single round of Edman degradation, which liberates ATZ-Gly. Another sample of the peptide is treated with trypsin, and a third sample is treated with chymotrypsin. The table below shows the fragments. Complete parts (a) and (b) below.

Map o Tryptic fragments Tyr-Ser Gly-Asp-Trp-Arg Asn-Tyr-Ala-Pro-Thr-Cys-Asn-Gln-Lys Ser Arg-Asn-Ty Ala-Pro-Thr-Cys-Asn-GIn-Lys-Tyr Gly-Asp-Trp a) Line up the fragments below so that fragments with the same sequences overlap. Drag each fragment to the appropriate location Gly-Asp-Trp Ala-Pro-Thr-Cys-Asn-Gln-Lys-Tyr Gly-Asp-Trp-Arg Arg-Asn-Tyr Tyr-Ser Asn-Tyr-Ala-Pro-Thr-Cys-Asn-Gin-Lys Ser continued below...

Explanation / Answer

from edman degradation the N terminal residue is labeled and it is glycine

trypsin predominantly cleaves proteins at the carboxyl side (or "C-terminal side") of the amino acids lysine and arginine except when either is bound to a C-terminal proline

Chymotrypsin preferentially cleaves peptide amide bonds where the carboxyl side of the amide bond (the P1 position) is a large hydrophobic amino acid (tyrosine, tryptophan, and phenylalanine).

Gly-Asp-Trp-Arg - Asn-Tyr-Ala-Pro-Thr-Cyc-Asn-Gln-lys - Tyr-ser

                 2                3                                 1        from trypsin digestion

4*,1* ,2*, 3* will be order for chymotrypsin digestion

2,1*,4*,3,2*,1,3*

order from the blue coloured boxes will be if you consider 1 to 7

1.3,4,6,2,5,7

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.