Given the following: Finding Percent H 2 O 2 with Yeast Volume of O 2 collected

Question

                    Given the following: Finding Percent H2O2 with Yeast                 

                    Volume of O2 collected = .014L                 

                    Temperature of water (in K): 299k                 

                    Pressure (in atm): 0.04 atm                 

a) What are the actual moles of O2 collected ?                 

b)What are the theoretical moles of O2 (assume 100% H2O2 density = 1.02 g/mL):?                 

c) What is the Percent H2O2: and the Reaction rate: ?                 

Show work                 

Explanation / Answer

a)Using PV/T =constant gives 0.04*0.014/299 =1*V/273 gives V=0.513ml.

Hence number of moles are PV/RT =1*5.13x10^-4/(0.0821)*273 =2.23x10^-5 moles.

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