K is the rate constant, A A is the frequency factor, E a Ea is the activation en

Question

K is the rate constant, A A is the frequency factor, E a Ea is the activation energy, R =8.314 (J/mol*k) is the universal gas constant, and T T is the absolute temperature. A certain reaction has an activation energy of 69.0kJ/mol and a frequency factor of A 1 = 2.60 times 1012M ?1 s ?1. What is the rate constant, k , of this reaction at 26.0 ? C? Express your answer with the appropriate units. Indicate the multiplication of units explicitly either with a multiplication dot (asterisk) or a dash.

Explanation / Answer

Since k = A * e^(Ea / R*T)

So we have k = 2.60* 10^12 M-1s-1 *e(- 69 *10^3 J/ (8.314 J/mol * K * 299K ) )

So k = 2.60 * 10^12 M-1s-1 * 8.8189 *10^-13(No units)

k = 2.2929 M-1s-1

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