I need to determine the molar mass of an unknown acid that is monoproctic. My fi

Question

I need to determine the molar mass of an unknown acid that is monoproctic.

My first titration led me to find that NaOH (the base) had a concentration avg of 0.00473 mol. At the equivalence point, moles of base = moles of acid. KHP is the known acid used in the first titration. I need to determine it's concentration.

The KHP solution is 1g KHP dissolved in 25 ml DI water. So I assumed that M KHP = #moles/0.0025L

so 0.00473 mol/0.0025 L = 0.1892 M ~~ 0.2 M

Is this correct?

If so, how do I go about determing the molar mass of an unknown acid that is monoproctic?

Explanation / Answer

vol = 25 ml =25/1000 = 0.025 liters

at equi moles of NAOH = moles of acid(KHP)

0.00473 = moles of KHP

0.00473 = mass of KHP/molar mass

0.00473 = 1/Molar mass

Molar mass = 211.416 gm/mol

KHP conc = 0.00473/0.025 = 0.1892 = 0.19 M

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