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You are given a 10.0-gram mixture of KOH and Ba(OH) 2 . Both are colorless ionic

ID: 788048 • Letter: Y

Question

You are given a 10.0-gram mixture of KOH and Ba(OH)2. Both are colorless ionic solids that are soluble in water. You dissolve this mixture in 250.0 mL of water and titrate with 1.50-molar hydrochloric acid. The endpoint is reached with 108.9 mL of the acid. Determine the mass of each substance in the original mixture.

...essentially I get to figuring out the moles of HCl but then am at a loss as to what to do. Please show your work :) You are given a 10.0-gram mixture of KOH and Ba(OH)2. Both are colorless ionic solids that are soluble in water. You dissolve this mixture in 250.0 mL of water and titrate with 1.50-molar hydrochloric acid. The endpoint is reached with 108.9 mL of the acid. Determine the mass of each substance in the original mixture.

...essentially I get to figuring out the moles of HCl but then am at a loss as to what to do. Please show your work :) You are given a 10.0-gram mixture of KOH and Ba(OH)2. Both are colorless ionic solids that are soluble in water. You dissolve this mixture in 250.0 mL of water and titrate with 1.50-molar hydrochloric acid. The endpoint is reached with 108.9 mL of the acid. Determine the mass of each substance in the original mixture.

...essentially I get to figuring out the moles of HCl but then am at a loss as to what to do. Please show your work :) You are given a 10.0-gram mixture of KOH and Ba(OH)2. Both are colorless ionic solids that are soluble in water. You dissolve this mixture in 250.0 mL of water and titrate with 1.50-molar hydrochloric acid. The endpoint is reached with 108.9 mL of the acid. Determine the mass of each substance in the original mixture.

...essentially I get to figuring out the moles of HCl but then am at a loss as to what to do. Please show your work :) You are given a 10.0-gram mixture of KOH and Ba(OH)2. Both are colorless ionic solids that are soluble in water. You dissolve this mixture in 250.0 mL of water and titrate with 1.50-molar hydrochloric acid. The endpoint is reached with 108.9 mL of the acid. Determine the mass of each substance in the original mixture.

...essentially I get to figuring out the moles of HCl but then am at a loss as to what to do. Please show your work :)

Explanation / Answer

the moles of Hcl= 0.16335 moles

let the mixture contain x gm of KOH and (10-x) gm of Ba(OH)2

moles of KOH= x/56

moles of Ba(OH)2= (10-x)/171

moles of OH- ions= x/56 + 2*(10-x)/171


x/56 + 2*(10-x)/171= 0.16335

taking LCM

(171*x + 56*2*(10-x)) / (171*56) = 0.16335

(59x+1120) / (9576)= 0.16335

59x + 1120 = 1564.2396

59x = 444.2396


x=7.529 gms


mass of KOH= 7.529 gm

mass of Ba(OH)2= 2.471 gm

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