Calculate how many grams of copper(II) carbonate are obtained when 2.0 mL of an

Question

Calculate how many grams of copper(II) carbonate are obtained when 2.0 mL of an 8.0 M aqueous solution of sodium carbonate is mixed with 10.0 mL of a 5.0 M aqueous solution of copper(II) nitrate.

The reaction proceeds according to the following reaction:

Cu(NO3)2(aq ) + Na2CO3(aq) -> CuCO3(s) + 2 NaNO3(aq)

The mass of copper(II) carbonate is_____x10^_____g.  Please Explain

Calculate how many grams of copper(II) carbonate are obtained when 2.0 mL of an 8.0 M aqueous solution of sodium carbonate is mixed with 10.0 mL of a 5.0 M aqueous solution of copper(II) nitrate. The reaction proceeds according to the following reaction: Cu(NO3)2(aq ) + Na2CO3(aq) -> CuCO3(s) + 2 NaNO3(aq) The mass of copper(II) carbonate is x10^ g. Please Explain

Explanation / Answer

we go by mole concept we have 16 millimoles of cu2[no3]2 and 50 millimoles of na2co3 so the limiting reagent is of 16 millimoles so 16 millimoles of cuco3 is formed

terefore gms =.016*123.5= 1.976

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