Chemical Equation of 1.0 M NaOH + 6.0M HCl yields..... I have NaOH + HCl= NaCl +
ID: 788447 • Letter: C
Question
Chemical Equation of 1.0 M NaOH + 6.0M HCl yields.....
I have NaOH + HCl= NaCl + H2O
correct?
(not sure with the subscripts 1.0M and 6.0 ... if those make a difference or not)
Thanks!
Explanation / Answer
NaOH + HCl ------> NaCl + H2O Molarity here will come to picture only when you'll be calculating the no of moles of the of the products, that corresponds to the no of moles of the reactants here. So, no of moles of NaOH = Molarity* volume (in litre) = 1*vol(in litre) No of moles of HCl = 6* vol (in litre) Thus, as the reaction yields 1 mole of NaCl from 1 mole each of HCl and NaOH, the one among NaOH and HCl having least no of moles will be the limiting reagent, hence the no of moles of product NaCl formed = no of moles of limiting reagent. Hope this helps. Thanks.
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