A 72kg man stands on a spring scale in an elevator. Startingfrom rest, the eleva

Question

A 72kg man stands on a spring scale in an elevator. Startingfrom rest, the elevator acsends, attaining its maximum speed of 1.2m/s in 0.80 s. The elevator travels with this constant speed for5.0 s, undergoes a uniform negative acceleration for 1.5 s, andthen comes to rest. Whatdoes the spring scale register (a)beforethe elevator starts to move? (b) during the first 0.80 s ofthe elevator's ascend? (c) while the elevator is traveling atconstant speed? (d) during the elevator's negativeacceleration?
Please be specific as possible! I am trying to learn this, not just get an answer A 72kg man stands on a spring scale in an elevator. Startingfrom rest, the elevator acsends, attaining its maximum speed of 1.2m/s in 0.80 s. The elevator travels with this constant speed for5.0 s, undergoes a uniform negative acceleration for 1.5 s, andthen comes to rest. Whatdoes the spring scale register (a)beforethe elevator starts to move? (b) during the first 0.80 s ofthe elevator's ascend? (c) while the elevator is traveling atconstant speed? (d) during the elevator's negativeacceleration?
Please be specific as possible! I am trying to learn this, not just get an answer

Explanation / Answer

The spring scale register measures the weight of the object with respect to the frame of the elevator

a) Before it starts reading = m * g = 72 * 9.8 N = 705.6 N

b) acceleration = 1.2/0.8 = 1.5 m/s^2

At the ascent reading = m *(g+a) = 72(9.8+1.5) = 813.6 N

c) At constant speed reading = m*g = 705.6 N

d) a' = 1.2 / 1.5 = 4/5 = 0.8 m/s^2

Reading = m *(g-a) = 72*9 = 648 N

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