Based on the values given in discussion question 3.21 of the text, estimate the

Question

Based on the values given in discussion question 3.21 of the text, estimate the standard Gibbs energy, enthalpy and entropy changes involved in the formation of a hairpin loop of the following sequence of DNA.

5’-CCCACCGTGAGTCATCGCTAGACTCACGGTAAA-3’

Here are the values given in discussion question 3.21 of the text:

Sequence                            5’-A-G   5’-G-C   5’-T-G

                                                3’-T-C    3’-C-G   3’-A-C

seqG/(KJ mol-1)              -5.4        -10.5      -6.7

seqH/(KJ mol-1)               -25.5      -46.4      -31.0

seqS/(KJ mol-1)                -67.4      -118.8    -80.8

This is for an upper division physical biochemistry class. please show all work. will rate thank you

You MUST use the given values or you will not recieve a positive rating. Thank you

Explanation / Answer

In given question, all the possible combination of base pair that form hairpin like structure was not given. Strongest hair pin loop like structure in the given DNA sequence is formed by the 20 bases.

5’-CCCACCGTGAGTCATCGCTAGACTCACGGTAAA-3’

In this question all the possible combinations of different thermodynamic parameter was not given.

On the basis of given values only one structure that making strongest hair pin loop is.

5’-CCCACCGTGAGTCATCGCTAGACTCACGGTAAA-3’

In this DNA5’GC and 3’CG pairing was not observed.

Parameters calculated according to given values:

S= -80.8+ (-67.4)

-148.2 KJ/mol

H= -31 +(-25.5)

-56.5 KJ/mol

G= -5.4+(-6.7)

-12.1 KJ/mol

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