Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl

Question

                    Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)=ZnCl2(aq)+H2(g)
How many milliliters of 6.00 M HCl(aq) are required to react with 5.65 g of Zn(s)?                     Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)=ZnCl2(aq)+H2(g)
How many milliliters of 6.00 M HCl(aq) are required to react with 5.65 g of Zn(s)?                Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)=ZnCl2(aq)+H2(g)
How many milliliters of 6.00 M HCl(aq) are required to react with 5.65 g of Zn(s)?           Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)=ZnCl2(aq)+H2(g)
How many milliliters of 6.00 M HCl(aq) are required to react with 5.65 g of Zn(s)?           Zinc reacts with hydrochloric acid according to the reaction equation      Zinc reacts with hydrochloric acid according to the reaction equation Zinc reacts with hydrochloric acid according to the reaction equation

Explanation / Answer

moles of Zn = 5.65 / 65.38 = 0.0864 moles

Moles of HCl required = 0.0864 x 2 = 0.173 moles

0.173 = 6 x V

=> V = 0.0288 liters = 28.8 mL

Related Questions

Navigate

• Browse (All)
• Browse Z
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.