Zinc reacts with phosphoric acid (H 3 PO 4 ) as shown in Equation 2, to form zin

Question

Zinc reacts with phosphoric acid (H3PO4) as shown in Equation 2, to form zinc phosphate and hydrogen gas.

3Zn (s) + 2H3PO4 (aq) = Zn3(PO4)2 (aq) + 3H2 (g)   (Equation 2)

This reaction was carried out using 13.08 g of zinc in 0.500 dm3 of phosphoric acid solution.

What is the volume of hydrogen gas given off?

Assume the reaction was carried out at a room temperature of 25C and 1 atmosphere of pressure and Assume that 1 mole of any gas at one atmosphere pressure and 25C occupies volume of 24.5 dm^3.

Explanation / Answer

The number of mols of Zn = 13.08 g / 65.41 g/mol = 0.199 mol

Therefore number of mols of H2 gas given off = (0.199 mol Zn)(3 mol H2 / 3 mol Zn) = 0.199 mol H2

Since 1 mol of any gas occupies 24.5 dm3 , hence 0.199 mol H2 gas occupies = 0.199 mol * 24.5 dm3 = 4.90 dm3

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